So first byte is E3 (binary 11100011), so & 0x0F is 0x0B. Second byte is 82 (10000010) → & 0x3F is 0x02. Third byte is AB (10101011) → & 0x3F is 0xAB? Wait, AB is 0xAB, which is 10 in hexadecimal. But 0xAB is 171 in decimal. Wait, but 0xAB is 171.
So the title could be "Caribbean Komo 062212-055". But why is it written in Japanese katakana? Maybe it's a brand name or product code.
Wait, first byte is E3 (hex), which is 227 in decimal. The UTF-8 three-byte sequence for code points in U+0800 to U+FFFF starts with 1110xxxx, and the code point is calculated as ((first byte & 0x0F) << 12) | ((second byte & 0x3F) << 6) | (third byte & 0x3F). So first byte is E3 (binary 11100011), so & 0x0F is 0x0B
Looking up Unicode code point U+B2AB... Hmm, that's not right. Wait, perhaps I made an error in the calculation. Let me recheck.
E3 in hex is 227, 82 is 130, AB is 171. So the bytes are 0xEB, 0x82, 0xAB. In UTF-8, three-byte sequences are for code points from U+0800 to U+FFFF. The first three bytes for "カ" (k katakana ka) should be 0xE381AB? Wait, maybe I need to refer to a Japanese encoding table. Wait, AB is 0xAB, which is 10 in hexadecimal
First segment: %E3%82%AB: E3 82 AB → Decode in UTF-8. Let's do this properly.
Each %E3%82%AB is a three-byte sequence: So the title could be "Caribbean Komo 062212-055"
Wait, the decoded string is "カリビアンコモ 062212-055". Let me verify each part: