M Karim Physics Numerical Book Solution Class 11 ❲95% WORKING❳

Using the equation: $$f = \mu N$$, where $\mu$ is the coefficient of friction and $N$ is the normal reaction.

Given: $v = 20$ m/s, $u = 0$ m/s, $t = 5$ s m karim physics numerical book solution class 11

$$a = \frac{20}{5} = 4$$ m/s²

$$20 - f = 5 \times 2$$

Using Newton's second law of motion: $$F - f = ma$$, where $F$ is the applied force, $f$ is the frictional force, $m$ is the mass, and $a$ is the acceleration. Using the equation: $$f = \mu N$$, where

Given: $F = 20$ N, $m = 5$ kg, $a = 2$ m/s² $u = 0$ m/s